[求助]fstream 的输出输入目录在哪？？？

羽衣独舞

cout<<"Entert the name of the input file:";
string inputFileName;
getline(cin,inputFileName);
ifstream inStream;
inStream.open(inputFileName.data());
assert(inStream.is_open());




cout<<"Enter the name of the output file:";
string outputFileName;
getline(cin,outputFileName);

ofstream outStream(outputFileName.data());
assert( outStream.is_open() );



例如我要读入 1 2 3 4 5 6
该在哪创建一个inputName? 和输出名字 outputFileName?
VC6.0

罗ぷ曼ㄉ帝Ke

当前目录，就是你的工程目录

first

以下是引用maoguoqing在2007-8-22 14:12:43的发言：

当前目录，就是你的工程目录
刚刚学到，不懂啊
书上没流程。。。。

☆冬虫草☆

你的源文件保存的地方

鰰﹎話

以下是引用maoguoqing在2007-8-22 17:19:05的发言：
你的源文件保存的地方
怎么还是读取不到的，晕。
保存源文件的几个文件夹都放过，
文件是： test.dat 读取时也是test.dat
怎么不行啊 晕。

依然范特西

那用inputFileName.c_str()式一下

☆独吻☆

不行啊，是不是我用的格式不对啊？
我用写字板写数字上去的，然后就改文件名

市井游侠々

你把完整的代码贴上来吧

王者风范

include<fstream>
#include<iostream>
#include<string>
#include<cassert>
#include<cfloat>
using namespace std;
int main()
{
cout<<" This program computes the number, maximum,minimum,and\n"
<<"average of an input list of numbers in one file,\n"
<<"and places its results in another file.\n\n";
//--------------------------输入部分----------------------------
cout<<"Entert the name of the input file:";
string inputFileName;
getline(cin,inputFileName);
ifstream inStream;
inStream.open(inputFileName.data());
assert(inStream.is_open());
int count=0;
double reading,
maximum=DBL_MIN,
minimum=DBL_MAX,
sum=0;
for(;;){
inStream>>reading;
if( inStream.eof() )
break;
count++;
sum+=reading;
if (reading<minimum)
minimum=reading;
if(reading>maximum)
maximum=reading;
}
inStream.close();
//-------------------------------------------
cout<<"Enter the name of the output file:";
string outputFileName;
getline(cin,outputFileName);
ofstream outStream;
outStream.open(outputFileName.data());
assert( outStream.is_open() );
outStream<<"\n-->There were"<<count<<"values";
if(count>0)
outStream<<"\n\tranging from"<<minimum
<<" to "<<maximum
<<"\n\tand their average is " <<sum/count
<<endl;
outStream.close();
cout<<"processing complete.\n";
return 0;
}

劳资ぶ龍哥

只是读取不到要打开的文件