书上的例程，为什么我编译总出现错误

小点点14504

// tempover.cpp --- template overloading
#include <iostream>
template <typename T> // template A
void ShowArray(T arr[], int n);
template <typename T> // template B
void ShowArray(T * arr[], int n);
struct debts
{
char name[50];
double amount;
};
int main(void)
{
using namespace std;
int things[6] = {13, 31, 103, 301, 310, 130};
struct debts mr_E[3] =
{
{"Ima Wolfe", 2400.0},
{"Ura Foxe", 1300.0},
{"Iby Stout", 1800.0}
};
double * pd[3];
// set pointers to the amount members of the structures in the arr mr_E
for (int i = 0; i < 3; i++)
pd[i] = &mr_E[i].amount;

cout << "Listing Mr. E's counts of things:\n";
// things is an array of int
ShowArray(things, 6); // uses template A
cout << "Listing Mr. E's debts:\n";
// pd is an array of pointers to double
ShowArray(pd, 3); // uses template B (more specialized)
return 0;
}
template <typename T>
void ShowArray(T arr[], int n)
{
using namespace std;
cout << "template A\n";
for (int i = 0; i < n; i++)
cout << arr[i] << ' ';
cout << endl;
}
template <typename T>
void ShowArray(T * arr[], int n)
{
using namespace std;
cout << "template B\n";
for (int i = 0; i < n; i++)
cout << *arr[i] << ' ';
cout << endl;
}
这是c++ primer plus(第五版)的一道例题（程序8.14)，可是我怎么编译都是不通过，我的编译器是VC6.0。错误原因是
void ShowArray(T arr[], int n)
{
using namespace std;
cout << "template A\n";
for (int i = 0; i < n; i++)
cout << arr[i] << ' ';
cout << endl;
}
template <typename T>
void ShowArray(T * arr[], int n)
{
using namespace std;
cout << "template B\n";
for (int i = 0; i < n; i++)
cout << *arr[i] << ' ';
cout << endl;
}
无法匹配，你们会出现这样的问题吗？
error C2667: 'ShowArray' : none of 2 overload have a best conversion
error C2668: 'ShowArray' : ambiguous call to overloaded function

人杰地灵

是不能重载吗？看字面！