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在ASP.NET中实现多文件上传

2010-1-31 07:49| 发布者: admin| 查看: 24| 评论: 0|原作者: 云天青

在以前的Web应用中,上传文件是个很麻烦的事,现在有了.NET,文件上传变得轻而易举。下面的这个例子实现了多文件上传功能。可以动态添加输入表单,上传的文件数量没有限制。代码如下:
MultiUpload.aspx
<%@ Page Language="vb" AutoEventWireup="false" Codebehind="MultiUpload.aspx.vb"
Inherits="aspxWeb.MultiUpload" %>



多文件上传














Font-Size="9pt" Width="500px" BorderStyle="None" BorderColor="White">





后代码:MultiUpload.aspx.vb
Public Class MultiUpload
Inherits System.Web.UI.Page
Protected WithEvents Upload As System.Web.UI.WebControls.Button
Protected WithEvents MyTitle As System.Web.UI.WebControls.Label
Protected WithEvents strStatus As System.Web.UI.WebControls.Label
#Region " Web Form Designer Generated Code "
'This call is required by the Web Form Designer.
Private Sub InitializeComponent()
End Sub
Private Sub Page_Init(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Init
'CODEGEN: This method call is required by the Web Form Designer
'Do not modify it using the code editor.
InitializeComponent()
End Sub
#End Region
Private Sub Page_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load
MyTitle.Text = "

多文件上传

"
Upload.Text = "开始上传"
If (Me.IsPostBack) Then Me.SaveImages()
End Sub
Private Function SaveImages() As System.Boolean
'遍历File表单元素
Dim files As System.Web.HttpFileCollection = System.Web.HttpContext.Current.Request.Files
'状态信息
Dim strMsg As New System.Text.StringBuilder("上传的文件分别是:
")
Dim iFile As System.Int32
Try
For iFile = 0 To files.Count - 1
'检查文件扩展名字
Dim postedFile As System.Web.HttpPostedFile = files(iFile)
Dim fileName, fileExtension As System.String
fileName = System.IO.Path.GetFileName(postedFile.FileName)
If Not (fileName = String.Empty) Then
fileExtension = System.IO.Path.GetExtension(fileName)
strMsg.Append("上传的文件类型:" + postedFile.ContentType.ToString() + "
")
strMsg.Append("客户端文件地址:" + postedFile.FileName + "
")
strMsg.Append("上传文件的文件名:" + fileName + "
")
strMsg.Append("上传文件的扩展名:" + fileExtension + "

")
'可根据扩展名字的不同保存到不同的文件夹
postedFile.SaveAs(System.Web.HttpContext.Current.Request.MapPath("images/") + fileName)
End If
Next
strStatus.Text = strMsg.ToString()
Return True
Catch Ex As System.Exception
strStatus.Text = Ex.Message
Return False
End Try
End Function
End Class

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